jjdeharo_Potencias

Ejercicios del libro, página 34, nº 26

math {\rm a)}\,\left( {\displaystyle\frac{5}{6}} \right)^2 = \displaystyle\frac

{\rm b)}\,\left( {\displaystyle\frac{3}{4}} \right)^{ - 3} = \left( {\displaystyle\frac{4}{3}} \right)^3 = \displaystyle\frac

{\rm c)}\,\left( {\displaystyle\frac{3}{4}} \right)^3 = \displaystyle\frac

{\rm d)}\,\left( {\displaystyle\frac{2}{3}} \right)^{ - 5} = \left( {\displaystyle\frac{3}{2}} \right)^5 = \displaystyle\frac

math